Info

此问题已关闭。 请重新打开它进行编辑或回答。

The code below generates random points inside a regular hexagon. I need the second coordinate y of the points to be an angle from 0:2pi. How can I modify the code please?

1 次查看（过去 30 天）
Jenny
Jenny 2018-1-21
关闭： MATLAB Answer Bot 2021-8-20
numEdges = 6;
R = 8;
xVertex = R * cos((0:6)*pi/3);
yVertex = R * sin((0:6)*pi/3);
xVertex = [xVertex , xVertex(1)];
yVertex = [yVertex , yVertex(1)];
requiredPoints = 20;
plot(xVertex, yVertex, 'b+-', 'LineWidth', 3);
grid on;
numPointsIn = 1;
while numPointsIn < requiredPoints
testx = 2 * R * rand(1) - R;
testy = 2 * R * rand(1) - R;
if inpolygon(testx, testy, xVertex, yVertex)
x(numPointsIn) = testx;
y(numPointsIn) = testy;
numPointsIn = numPointsIn + 1;
end
end
hold on;
plot(x,y,'r+', 'MarkerSize', 10, 'LineWidth', 2);

请先登录，再回答此问题。

回答（1 个）

Image Analyst
Image Analyst 2018-1-21
Something like
yAngle = atan2(y, x);
  7 个评论
显示 5更早的评论
Image Analyst
Image Analyst 2018-1-21
yAngle is in the range 0-2*pi, not -8 to 8. y is in that range, but not the angles.
To have the angle show up on the graph, use the sprintf() and text() functions.
str = sprintf('yAngle(1) = %f', yAngle(1));
text(1., .2, str);

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by