About checking each elements in a vector using if loop (some what...)

Hello I'm new to MATLAB and I'd like to check an inputted array, which contain non-numeric elements and perform plotting, the code is as follow:
filename = 'HetCtxDIV1720164171motion.xls';
x = xlsread(filename,'D:D');
t = xlsread(filename,'C:C');
y = xlsread(filename,'E:E');
d = xlsread(filename,'B:B');
if isnumeric(d(i))
if isnumeric(t(i+2))
t1(i:i+600) = t(i+3:i+603);
x1(i:i+600) = x(i+3:i+603);
y1(i:i+600) = y(i+3:i+603);
tc = (t1)/(max(t1))
c = tc;
sz = 30;
scatter(x1,y1,sz,c,'filled');
colorbar('Ticks',[(0.1),(0.2),(0.3),(0.4),(0.5),(0.6),(0.7),(0.8),(0.9)],'TickLabels',
{'0.1','0.2','t=0.3','0.4','0.5','0.6','0.7','0.8','0.9*fulltime'})
end
end
however, output t1 is an empty vector...why?

4 个评论

@LEE Min Hsun: What is i, and where is it defined?
i is refer to elements in vectors(d,t,x,y), and it's not defined.
If i is not defined what value do you expect it to have? (hint: think about complex numbers).
seems like d(i) shall not exist cause there shall not have "i"th element in d, but isnumeric(d(i)) turn out to be true...?

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