replace element in the vector without using loops or if statement
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using a logical vector and a single line of code (3 total lines if you count the “function” line and the “end” line). Your function should not have any loops or if statements in it. (You should assume the input is a row vector.)
here is the given code:
function [ y ] = nottwo( v )
y = [];
for i = 1:length(v)
if v(i)~= 2
y = [y, 0];
else
y = [y, 10];
end
end
采纳的回答
Star Strider
2018-1-25
It is difficult to help without giving away the solution.
To use a logical vector to address the array, see what this example code is doing:
v = randi(9, 1, 20)
LogicalIndex = v ~= 2
3 个评论
Walter Roberson
2018-1-25
Hint: logical vectors can be multiplied by a constant such as 10.
siemcheng ngor
2018-1-25
Star Strider
2018-1-25
Please see the documentation on Matrix Indexing I linked to.
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