I have lots of wave file. How do I read each one of them using sprintf command?

1 次查看(过去 30 天)
The wave file are like.The first digit- speaker id, second digit-utterence id
  • 00
  • 01
  • 02
  • 03
  • 04
  • .
  • .
  • .
  • 59
I tried using
for m=0:5
for y=0:9
file=sprintf('%s%d%d','E:\0 (1)\0\',m,y);
[s,fs]=wavread(file);
end
end
But this gives error. Alternatively I tried
mypath = 'E:\\0 (1)\\0\\';
filename = sprintf([mypath '%s%d.wav'],m,y);
[s,fs] = audioread(filename);
But it gave error as : Function is not defined for sparse inputs.
Please help me.

采纳的回答

Walter Roberson
Walter Roberson 2018-1-28
mypath = fullfile('E:', '0 (1)', '0');
for m = 0 : 5
for y = 0 : 9
filename = fullfile(mypath, sprintf('%d%d.wav', m, y));
[s, fs] = audioread(filename);
...
end
end
Or in your situation you could use a single loop:
mypath = fullfile('E:', '0 (1)', '0');
for idx = 0 : 59
filename = fullfile(mypath, sprintf('%02d.wav', idx));
[s, fs] = audioread(filename);
...
end
  4 个评论
Image Analyst
Image Analyst 2018-1-28
Your first code:
for m=0:5
for y=0:9
file=sprintf('%s%d%d','E:\0 (1)\0\',m,y);
[s,fs]=wavread(file);
end
end
gets the file (perhaps) but doesn't do anything with the s and fs it retrieved.
There are ways you could make your code more robust, for example by checking in advance if the file exists before calling wavread(), and by updating to the new function audioread(), etc.
See the FAQ.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Variables 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by