I have lots of wave file. How do I read each one of them using sprintf command?

Question

sangeet sagar 2018-1-28

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/379386-i-have-lots-of-wave-file-how-do-i-read-each-one-of-them-using-sprintf-command

评论： Walter Roberson 2018-1-28

采纳的回答： Walter Roberson

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The wave file are like.The first digit- speaker id, second digit-utterence id

00
01
02
03
04
.
.
.
59

I tried using

for m=0:5
for y=0:9
 file=sprintf('%s%d%d','E:\0 (1)\0\',m,y);
 [s,fs]=wavread(file);
end
end

But this gives error. Alternatively I tried

mypath = 'E:\\0 (1)\\0\\';
filename = sprintf([mypath '%s%d.wav'],m,y); 
 [s,fs] = audioread(filename);

But it gave error as : Function is not defined for sparse inputs.

Please help me.

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Answer 1

Walter Roberson 2018-1-28

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https://ww2.mathworks.cn/matlabcentral/answers/379386-i-have-lots-of-wave-file-how-do-i-read-each-one-of-them-using-sprintf-command#answer_302128

在 MATLAB Online 中打开

mypath = fullfile('E:', '0 (1)', '0');
for m = 0 : 5
  for y = 0 : 9
    filename = fullfile(mypath, sprintf('%d%d.wav', m, y));
    [s, fs] = audioread(filename);
    ...
 end
end

Or in your situation you could use a single loop:

mypath = fullfile('E:', '0 (1)', '0');
for idx = 0 : 59
  filename = fullfile(mypath, sprintf('%02d.wav', idx));
  [s, fs] = audioread(filename);
    ...
end

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Image Analyst 2018-1-28

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Your first code:

for m=0:5
    for y=0:9
       file=sprintf('%s%d%d','E:\0 (1)\0\',m,y);
       [s,fs]=wavread(file);
    end
end

gets the file (perhaps) but doesn't do anything with the s and fs it retrieved.

There are ways you could make your code more robust, for example by checking in advance if the file exists before calling wavread(), and by updating to the new function audioread(), etc.

See the FAQ.