simulink double value into a logical type error

2018 1 30
1 个回答
更新时间：2018 1 30
17 次查看（30 天）

0 个投票

if true
function y = ratioimg(u)
[L2,num2]=bwlabel(u,8); %連通區域標記
B2=false(size(u));
for i=1:num2
[r,c] = find(L2==i);
left = min(c);
right = max(c);
up = min(r);
down = max(r);
d = (down-up) / (right-left);
if d > 0.7 & d < 1.42
% [x,y]=find(L2==i); % Done above already
B2 = B2 + bwselect(u, c, r, 8); %%%把滿足長寬比在0.8到2的區域留下
end
end
y = B2;
end
i use this function on the simulink but show the error

7 个评论
显示 5更早的评论 隐藏 5更早的评论

Birdman
Birdman 2018-1-30
Can you share your simulink model?
Birdman
Birdman 2018-1-30
编辑：Birdman 2018-1-30
Do you have to do the data type conversion inside a MATLAB Function block?
Birdman
Birdman 2018-1-30
Which line the conversion will take place? Be more specific.
KAI XUN CAI
KAI XUN CAI 2018-1-30
B2 = B2 + bwselect(u, c, r, 8); change double

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

Fangjun Jiang
Fangjun Jiang 2018-1-30

0 个投票

B2 is logical.
B2 = B2 + bwselect(u, c, r, 8)
should be
B2 = or(B2,bwselect(u, c, r, 8))

类别

在 帮助中心 和 File Exchange 中查找有关 Programmatic Model Editing 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by