homework help, my loglog wont plot a line
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function [] =FFAplot(a,b,k)
%UNTITLED Summary of this function goes here
% Detailed explanation goes here
A=size(a);
B=size(b);
K=size(k);
p=(1/100);
T=100;
if A(1,1)==B(1,1)
if A(1,2)==B(1,2)
if (B(1,1)==K(1,1))||(B(1,2)==K(1,2))
j=0;
i=1:K(1,2);
Qi=zeros((A(1,1)),(A(1,2)));
while j==0
% Qi=((b(1,i))+(((a(1,i))/(k(1,i)))*(1-((-log(1-p)).^(k(1,i))))));
loglog((10),(10^6),'r')
hold on
plot(T,((b(1,i))+(((a(1,i))/(k(1,i)))*(1-((-log(1-p)).^(k(1,i)))))),'r')
%loglog(((b(1,i))+(((a(1,i))/(k(1,i)))*(1-((-log(1-p)).^(k(1,i)))))),T)
end
end
end
end
end
MY code wont plot anything it keeps just giving me the graph with the x and y values but no ploted line
回答（1 个）
Star Strider
2018-1-30
It won’t because you didn’t tell it to. You told it to plot a point, and since the default behavoiur of plot is to connect two (or more) points with lines, it drew nothing.
If you want it to plot the point, plot a marker:
loglog((10),(10^6),'pr')
8 个评论
Faith Dominguez
2018-1-30
Walter Roberson
2018-1-30
编辑：Walter Roberson
2018-1-30
To plot a line, you need to pass a list of two or more points to one of the plotting functions.
... What you should be doing is storing the x and y coordinates that you are plotting at into a vector, and not plotting inside the loop. Plot the vectors after the loop.
I notice that your T is not changing, so your points would all be at x = 100. Is that what you wanted?
You are not changing j inside your loop, so your while j==0 is an infinite loop.
Star Strider
2018-1-30
It depends on what you want to plot.
Try this:
figure
loglog([1 10], [1 100000], 'b') % Plot Arbitrary Function
hold on
loglog(xlim, [1; 1]*[10 10^6],'-r') % Plot Parallel Red Lines
hold off
axis([xlim 1 1E+7]) % Set ‘axis’ Limits To Be Cure To Show Lines
Faith Dominguez
2018-1-30
编辑：Walter Roberson
2018-1-30
Walter Roberson
2018-1-30
I would suggest, though, that if you only have a single x value, that using a loglog plot does not make sense, that semilogy would make more sense.
Faith Dominguez
2018-1-30
Walter Roberson
2018-1-30
Ah.
With your T being constant you are only going to vertical lines.
Also when you use 'pr' you specify pentagram marker in red, but you would not get any line. You would need a line specification as well such as '-pr' to get lines. Which might fold back on themselves... I doubt you really want T (x coordinate) to be constant.
Star Strider
2018-1-30
Also, we never did resolve the problem of ‘K(1,2)’ being anything other than 1. If it is greater than 1, then ‘i’ is a vector. That is going to cause problems.
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2018-1-30
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