what do the variable P,I and D mean in PID(z) in simulink?

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Hello, As you saw in my question, do P.I and D means Ku(ultimate gain),Ti and Td respectively when using the PID from simulink? thanks
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Guillaume
Guillaume 2018-2-5
编辑:Guillaume 2018-2-5
We could turn back the question back on you and ask what do the variable Ku, Ti and Td mean for you?
They're obviously the proportional, integral and derivative constant respectively. What they mean exactly is completely documented in the help.

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SimTec
SimTec 2018-2-7
Hello Birdman and Thank you so much for your help. So what I understood is that I have to write the value in the PID(z) in simulink as showed in the pictures.is it correct!

更多回答(3 个)

Jim Riggs
Jim Riggs 2018-2-5
See the link to help in Guillaume's comment:
Proportional
Integral
Differential

SimTec
SimTec 2018-2-6
Sorry, My question was wrong. I know those what they mean but my question when it comes to tuning a PID. in the PID(z) controller, I see P,I and D, using Ziegler Nichols, SHould I put the value calculated like P=Ku,I=Ti and D=Td or P=Kp,I=Ki and D=Kd? thanks

Birdman
Birdman 2018-2-6
This question can be answered in different aspects but let me start from explaining them in this way:
If you are going to write IDEAL(not reasonable in this form) PID structure, you may write it as follows:
PID(s)=(Kd*s^2+Kp*s+Ki)/s
and also, a second form, which is also widely used IDEAL(not reasonable in this form), is as follows:
PID(s)=Ku*(1+(1/Ti*s)+(Td*s))
Which one to use is totally up to the user. In the first form, you can think of each term as independent because every term has its gain and by setting each of them, you design a PID. In second form, you have a global gain for your PID and time constants Ti and Td decides the weight of I and D term in your controller respectively.
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Birdman
Birdman 2018-2-7
Answer to
Hello Birdman and Thank you so much for your help. So what I understood is that I have to write the value in the PID(z) in simulink as showed in the pictures.is it correct!
See the attached figures, for both ideal and parallel PID, the thing that I explained in my answer.

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