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one-by-one matrix assignment

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Antonio
Antonio 2018-2-6
评论： Antonio 2018-2-6
I need to find the minimum values in each column of matrix "A", and then replace those min values with the values in last row of matrix "B" (which has same number of columns). Like I have these:
>> A = randi(10,10,5)
A =
3 5 9 5 8
7 6 4 10 2
8 4 1 7 4
4 7 2 8 2
7 5 8 7 5
3 7 10 10 1
5 7 8 5 7
8 3 8 2 3
6 10 2 1 10
3 7 6 7 2
>> B = randi(100,3,5)
B =
10 34 66 18 62
99 95 49 54 81
52 1 52 9 95
>> [M,I] = min(A)
M =
3 3 1 1 1
I =
1 8 3 9 6
And I want to replace the values of "M" with "B(end,:), so that:
A(1,1) = B(end,1);
A(8,2) = B(end,2);
A(3,3) = B(end,3);
A(9,4) = B(end,4);
A(6,5) = B(end,5);
I try "A(I) = B(end,:)" and "A(I(1,:)) = B(end,:)" but they do not work! Any ideas how I could do that? My real matrices are huge (1200x100000) so no way to do it by hand!
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Jos (10584)
Jos (10584) 2018-2-6
ok. then Andrei's answer suffices.
Antonio
Antonio 2018-2-6
@Jos (10584) great, thanks!

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采纳的回答

Andrei Bobrov
Andrei Bobrov 2018-2-6
编辑：Andrei Bobrov 2018-2-6
[~,idx] = min(A);
s = size(A);
A(sub2ind(s,idx,1:s(2))) = B(end,:);

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