Real value to binary
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How can i convert my real value to binary digits?
For example; i have values within [0,25] range and 15 binary digits to represent a variable.(4 variables totally)
How can i do that and also reverse of that?
3 个评论
Walter Roberson
2012-5-11
Fixed point or floating point? And to confirm, the input values are not necessarily integer?
25 requires 5 bits; should we assume 5 bits of integer and 10 bits of fraction?
b
2012-5-11
Walter Roberson
2012-5-11
3 decimal places requires 10 bits to resolve (2^(-10) = 1/1024)
You get slightly better resolution if you use 2^10 than if you use 10^3. It depends though on whether resolution is your goal or if "3 decimal places" is your goal.
采纳的回答
Sean de Wolski
2012-5-11
doc dec2bin
更多回答（3 个）
Honglei Chen
2012-5-11
Are you asking things like dec2bin and bin2dec?
x = 20;
dec2bin(20,15)
Walter Roberson
2012-5-11
dec2bin(round(Values * 2^10), 15) - '0'
5 个评论
b
2012-5-11
Walter Roberson
2012-5-11
Yes, enter you number in Values.
If your range is up to "just less than" 16, then
dec2bin(round(Values * 2^11), 15) - '0'
For 2.154 the result would be
001000100111011
The first 4 bits (0010) are the 2, and the last 11 bits approximate 0.154
b
2012-5-11
b
2012-5-11
Walter Roberson
2012-5-11
If you go up to 25 then you need the 2^10 not 2^11
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