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Real value to binary

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b
b 2012-5-11
How can i convert my real value to binary digits?
For example; i have values within [0,25] range and 15 binary digits to represent a variable.(4 variables totally)
How can i do that and also reverse of that?
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b
b 2012-5-11
it will be 3 places after the decimal point.
so i think that i will have 10^3*25 equal size.
that is equal to
2^14 < 25000 < 2^15. so i will have 15 bits. ??
Walter Roberson
Walter Roberson 2012-5-11
3 decimal places requires 10 bits to resolve (2^(-10) = 1/1024)
You get slightly better resolution if you use 2^10 than if you use 10^3. It depends though on whether resolution is your goal or if "3 decimal places" is your goal.

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采纳的回答

Sean de Wolski
Sean de Wolski 2012-5-11
doc dec2bin

更多回答（3 个）

Honglei Chen
Honglei Chen 2012-5-11
Are you asking things like dec2bin and bin2dec?
x = 20;
dec2bin(20,15)
Walter Roberson
Walter Roberson 2012-5-11
dec2bin(round(Values * 2^10), 15) - '0'
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b
b 2012-5-11
Sorry for that but i want to ask another thing..
my range is between 0 and 25.
when i put e.g. 2.5 to this formula,this gives me wrong result
Walter Roberson
Walter Roberson 2012-5-11
If you go up to 25 then you need the 2^10 not 2^11

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b
b 2012-5-11
Actually, if i put 2.154 as a real value within [0,25]
it should not give me 000000000000010. it represents for my range 0.001 something like that.

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