how to create this matrix [1 2 3 4 5;2 2 3 4 5;3 3 3 4 5;4 4 4 4 5;5 5 5 5 5]

4 次查看（过去 30 天）
Farooq Aamir
Farooq Aamir 2018-2-9
回答： Benjamin Drewry 2018-2-9
Waiting for your response
  1 个评论
John D'Errico
John D'Errico 2018-2-9
Why is it starting to look as if you are asking homework questions? This is now your second question on how to create a basic matrix?

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Jos (10584)
Jos (10584) 2018-2-9
编辑：Jos (10584) 2018-2-9
% data
n = 7 % "order"
% engine
x = repmat(1:n,n,1)
x = max(x, x.')
Added after comment: for non-square matrices:
n = 4 ; m = 6 ; % n-by-m matrix
x = max(repmat(1:m,n,1), repmat(1:n,m,1).')

更多回答（3 个）

Andrei Bobrov
Andrei Bobrov 2018-2-9
[x,y] = ndgrid(1:5)
out = max(x , y)
  3 个评论
显示 1更早的评论

请先登录，再进行评论。

Torsten
Torsten 2018-2-9
编辑：Torsten 2018-2-9
A = [1 2 3 4 5;2 2 3 4 5;3 3 3 4 5;4 4 4 4 5;5 5 5 5 5];
Best wishes
Torsten.
Benjamin Drewry
Benjamin Drewry 2018-2-9
Well super brute force method, but it helps if you are just beginning to code
clear all; close all; clc
M=5; N=5; % can vary M and N to matrix of size of interest
% preallocate matrix space
concat_matrix=ones(M,N);
j=1;
for i=1:M
if i>N
concat_matrix(i, :)=concat_matrix(i-1,:)+1;
else
repval=ones(1,j).*j;
remains=[numel(repval)+1:N];
concat_matrix(i,1:N)=[repval remains];
j=j+1;
end
end

类别

在 Help Center 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by