Unable to plot matrix multiples

2018 2 9
1 个回答
回答已采纳
更新时间：2018 2 9
2 次查看（30 天）

0 个投票

So I'm trying to plot the sum of a matrix at 25 different values using the code below, but matlab gives me the error " Error using ^ One argument must be a square matrix and the other must be a scalar. Use POWER (.^) for elementwise power. ", Even though x technically is a scalar (right?). Note that i am NOT trying to simply multiply the matrix by a constant x. For x=2 I want to compute A*A (matrix multiplication).
clear all
A = [1.9 0.025;0.1 1.225];
v = [1;0];
for i = 1:25 answer = sum((A^i)*v); end
answer
x = (1:25);
y = sum((A^x)*v);
plot (x,y)
xlabel('# of growth periods')
ylabel('Total # of bacteria')

请先登录，再回答此问题。

 采纳的回答

Birdman
Birdman 2018-2-9
编辑：Birdman 2018-2-9

0 个投票

A = [1.9 0.025;0.1 1.225];
v = [1;0];
for i = 1:25
answer(i) = sum((A^i)*v);
end
x = 1:25;
plot (x,answer)
xlabel('# of growth periods')
ylabel('Total # of bacteria')

2 个评论
显示 无 隐藏 无

Lukas Lehrman
Lukas Lehrman 2018-2-9
编辑：Lukas Lehrman 2018-2-9
Thank you for the answer! I've since ran into yet another problem. Now I'm trying to calculate a the value of an unknown that would generate the maximum value in a matrix, but i get the error "Subscripted assignment dimension mismatch".
pvalues = [0:0.01:1];
v = [1;0];
for i=1:length(pvalues)
p=pvalues(i)
A = [2-p 0.25*p;p (1.25-(0.25*p))];
answer(i) = (A^25)*v;
end
max(answer)
I thought i could work around it, but it seems that it hasn't worked.
Birdman
Birdman 2018-2-9
pvalues = 0:0.01:1;
v = [1;0];
for i=1:length(pvalues)
A = [2-pvalues(i) 0.25*pvalues(i);pvalues(i) (1.25-(0.25*pvalues(i)))];
res = (A^25)*v;
val(i)=max(res);
end

请先登录，再进行评论。

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Linear Algebra 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by