Sort all columns in a cell array with labels
显示 更早的评论
Hello everyone
I have the following cell array with text and numeric data:
>> M
M =
5×4 cell array
'' 'Ana' 'Delta' 'Oscar'
'B' [0.9058] [0.9058] [0.9058]
'C' [0.1270] [0.1270] [0.1270]
'D' [0.9134] [ 4] [ 2]
'E' [0.6324] [0.6324] [0.6324]
I would like to sort the data in columns 2, 3 and 4 in descending order (largest to smallest) but also with labels (column 1) and also with labels Ana, Delta and Oscar. I am aware that sortrows can be used for sorting data using a particular column, but I am not sure of the indexing for sortrows or an efficient way of sorting data in columns 2-4 in my cell array M and at the same time having labels next to them.
Thank you for your help.
Suha.
2 个评论
@Suha: you should really consider putting your data into a table, which natively store data with headers. Then you could apply lots of other functions to the data without having to worry about the first row and column being special cases, e.g. sorting the rows without requiring any indexing at all. It also stores the columns as arrays of an appropriate class, which makes working with the data much easier (putting lots of scalar numeric data into cells of a cell array just makes working with numeric data much more complex than it needs to be).
Suha
2018-2-13
采纳的回答
If you do not want to use a table then you would be better off keeping your numeric and cell-of-character data separately, e.g.:
hdr = {'Ana','Delta','Oscar'}
typ = {'B','C','D','E'};
mat = [0.9058,0.9058,0.9058;...
0.1270,0.1270,0.1270;...
0.9134, 4, 2;...
0.6324,0.6324,0.6324];
Then you can trivially sort by rows as you choose:
>> [mat,idx] = sortrows(mat)
mat =
0.12700 0.12700 0.12700
0.63240 0.63240 0.63240
0.90580 0.90580 0.90580
0.91340 4.00000 2.00000
idx =
1
2
3
4
>> typ = typ(idx);
>> typ{:}
ans = B
ans = C
ans = D
ans = E
5 个评论
Suha
2018-2-13
Stephen23
2018-2-13
"Could you please tell me if there is a way of modifying the command below so that idx comes out as a matrix for all sorted columns in mat"
It is not clear what you mean. Do you want to sort each column independently?
Suha
2018-2-13
Stephen23
2018-2-13
@Suha: each column might have a different order: is that what you want?
>> [mat,idx] = sort(mat,1)
mat =
0.12700 0.12700 0.12700
0.63240 0.63240 0.63240
0.90580 0.90580 0.90580
0.91340 4.00000 2.00000
idx =
2 2 2
4 4 4
1 1 1
3 3 3
>> out = typ(idx)
'C' 'C' 'C'
'E' 'E' 'E'
'B' 'B' 'B'
'D' 'D' 'D'
Suha
2018-2-14
更多回答（1 个）
Something like this?
[~,idx]=sort(cell2mat(M(2:end,2:end)),1,'descend');
M(sort(idx)+1,:)=M(idx+1,:)
or
[~,idx]=sortrows(M(2:end,2:end),'descend');
M(sort(idx)+1,:)=M(idx+1,:)
7 个评论
Suha
2018-2-13
Birdman
2018-2-13
What did you expect?
Suha
2018-2-13
Use this one,
[~,idx]=sort(cell2mat(M(2:end,2:end)),1,'descend');
M(sort(idx)+1,:)=M(idx+1,:)
Suha
2018-2-13
Birdman
2018-2-13
It worked perfectly in my case, where each column was sorted independently. Make sure you enter the code correctly, otherwise it should work. I can not attach a screenshot of it at the moment.
Suha
2018-2-14
类别
在 帮助中心 和 File Exchange 中查找有关 Shifting and Sorting Matrices 的更多信息
Translated by 
