Why does the second example fail?
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here's my code and the response
testvec = [Xc,Yc,sig,A]
ErrTest1 = RMS_Err_func(Image,Xc,Yc,sig,A)
ErrTest2 = RMS_Err_func(Image,testvec)
gives:
ErrTest1 =
0.0942
Not enough input arguments.
Error in NM_2D_Gauss_fit>RMS_Err_func (line 60)
r(l,m) = sqrt((l-Xc).^2+(m-Yc).^2);
Error in NM_2D_Gauss_fit (line 46)
ErrTest2 = RMS_Err_func(Image,testvec)
3 个评论
Walter Roberson
2018-2-13
NM_2D_Gauss_fit and RMS_Err_func appear to be your own code.
In your first call you are passing in four inputs to RMS_Err_func. In the second call you are only passing in two inputs. We can only guess that RMS_Err_func needs more than 2 inputs.
Derrick Salmon
2018-2-13
Walter Roberson
2018-2-13
... Yes?
You are passing it in to the function, so the second argument can examine the contents of testvec.
采纳的回答
Walter Roberson
2018-2-13
I suspect that your testvec is a vector that has within it values for Xc, Yc, sig, A . If so then,
temp = num2cell(testvec);
ErrTest2 = RMS_Err_funct(Image, temp{:});
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