How to remove non consecutive values from a vector?

2018 2 15
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更新时间：2018 2 15
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I have the following vector that represents how many times consecutive values appear in a row by using the following code:
x = [5 3 3 1 0 9 9 4 4 4 4 5 1 2 2];
y=[]
for i = 1:length(x)
a = length(find(x(1:i)==x(i)));
y=[y,a];
end
and I want a code to remove the 2 2 subelements from the resultant y matrix.
y= [1 1 2 1 1 1 2 1 2 3 4 2 2 1 2]

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Akira Agata
Akira Agata 2018-2-15
The last sentence of your question is not clear for me. Could you tell us more detail on it and provide what the final output of your example looks like?
GEORGIOS BEKAS
GEORGIOS BEKAS 2018-2-15
y= [1 1 2 1 1 1 2 1 2 3 4 1 1 1 2]

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Birdman
Birdman 2018-2-15

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y= [1 1 2 1 1 1 2 1 2 3 4 2 2 1 2]
idx=find(abs(diff(y))==2)+1;
y(idx:idx+1)=1

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GEORGIOS BEKAS
GEORGIOS BEKAS 2018-2-15
correct. but aby non consecutive has the relationship: idx=find(abs(diff(y))>=2)+1; y(idx:idx+1)=1

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