How I use fprintf to acess a struct?
19 次查看(过去 30 天)
显示 更早的评论
I have defined the struct written down.
SATS_Hour = struct('SATS_H0',[],'SATS_H1',[],'SATS_H2',[],'SATS_H3',[],...
'SATS_H4',[],'SATS_H5',[],'SATS_H6',[],'SATS_H7',[],...
'SATS_H8',[],'SATS_H9',[],'SATS_H10',[],'SATS_H11',[],...
'SATS_H12',[],'SATS_H13',[],'SATS_H14',[],'SATS_H15',[],...
'SATS_H16',[],'SATS_H17',[],'SATS_H18',[],'SATS_H19',[],...
'SATS_H20',[],'SATS_H21',[],'SATS_H22',[],'SATS_H23',[]);
I have to access a struct to write on each individual SATS_Hour.SATS_H0 for the first time of my loop, it contains 48 loops. The number after the letter H, of each variable, must change up to the last one 47.
How can I do this?
Using fprintf or other Matlab command?
Thanks for the help.
Gilberto Fernandes
0 个评论
采纳的回答
Guillaume
2018-2-15
编辑:Guillaume
2018-2-15
Numbering variables or structure fields is a bad idea. Any time you start naming things sequentially you need to think of using an array instead. Here, for example you'd be better off using a cell array. I.e use:
SATS_Hour = cell(23, 1); %instead of a structure
for idx = 1:23
SATS_Hour{idx} = ...
end
Indexing is always easier than awkward name construction via sprintf. If you're hell bent on using a structure:
for idx = 1:23
SATS_Hour.(sprintf('SATS_H%d', idx)) = ...
end
As you see, it's more complicated, less readable, and probably slower.
更多回答(2 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Dates and Time 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!