What is wrong with my while loop?

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Jet Verheij
Jet Verheij 2018-2-15
评论： Jet Verheij 2018-2-15
I have this big matrix, 592x528x903 single, called X. I want to see if the X(:,:,1) is not equal to any other in the matrix. I use this code:
b=2;
while b < 902
if X(:,:,1) ~= X(:,:,b)
b
end
b=b+1;
end
disp done
I get nothing on the screen, except done, so first I thought they all where equal. The problem is that if i use "equal to", i get the same response, nothing on the screen.
b=2;
while b < 902
if X(:,:,1) == X(:,:,b)
b
end
b=b+1;
end
disp done
Something is not working, they can't be both equal and not equal at the same time, or am I wrong?

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采纳的回答

Brendan Hamm
Brendan Hamm 2018-2-15
Your problem is that the result of
X(:,:,1) == X(:,:,b)
or
X(:,:,1) ~= X(:,:,b)
will return a logical matrix the same size as X(:,:,1) which apparently is never all true or all false and thus the if statement always evaluates to be false. The reson is this performs an element-wise comparison. If you want to check equality of the entire matrix, you should use the isequal function (isequaln if you want to ignore NaN in the matrices).
X = randi([0 1],2,2,902); % X with some equal pages.
b=2;
while b < 902
if isequal(X(:,:,1),X(:,:,b)) % or isequaln
b
end
b=b+1;
end
disp done

更多回答（1 个）

KL
KL 2018-2-15
编辑：KL 2018-2-15
Comparing matrices is easier if you use isequal command.
https://www.mathworks.com/help/matlab/ref/isequal.html
You should use it like,
if(isequal(X(:,:,1),X(:,:,b)))
What you're actually doing while using == or ~= is extracting a logical matrix as the result. Check this below example,
A = [1,2;3 4];
B = [1 0;3 4];
A==A
ans =
1 1
1 1
A==B
ans =
1 0
1 1
You see the problem?
Whereas, if you use isequal,
isequal(A,A)
ans =
1
isequal(A,B)
ans =
0

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