How do I use for loops and if statements to find numbers in a two dimensional array and replace them?

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BCLAcowgirl#1
BCLAcowgirl#1 2018-2-18
评论： Image Analyst 2021-10-3
I need to replace all the negative numbers in A=[1 2 4; 3 2 -1; 2 4 5; -2 -1 10] with zeros using for loops and if statements.
Below is the coding I have, but it doesn't do anything. Please, advise me on what I'm doing wrong.
for i=A
if i<0
A(i)=0;
end
end

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采纳的回答

Star Strider
Star Strider 2018-2-18
In your homework assignment that requires for loops and an if block, you need two nested loops, one looping through the rows and another the columns. In the innermost loop, use the if statement to test and replace the negative values of ‘A’, not the loop indices (that in MATLAB must be integers greater than zero, so a test for negative values of them will always fail).
There are more straightforward ways to do this, one being:
A = [1 2 4; 3 2 -1; 2 4 5; -2 -1 10];
A = A .* (A>0)
A =
1 2 4
3 2 0
2 4 5
0 0 10
I don’t mind showing you that solution, since you can’t use it in your assignment.

更多回答（3 个）

Roger Stafford
Roger Stafford 2018-2-18
编辑：Roger Stafford 2018-2-18
Use the "linear" form of the array:
for i = 1:length(A(:))
if A(i) < 0 % <- [Corrected]
A(i) = 0;
end
end
or you can do this:
t = A<0;
A(t(:)) = 0;
Image Analyst
Image Analyst 2018-2-18
Close, but you need to loop from 1 to numel(A) and you need to check if A(i) < 0, not if i < 0.
A=[1 2 4; 3 2 -1; 2 4 5; -2 -1 10]
for i = 1 : numel(A)
if A(i) < 0
A(i) = 0;
end
end
A
Patel Keyur
Patel Keyur 2021-10-3
I have one array and in this array detected number in this array so how to detected number in array?

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