According to SVD technique A=U*S*V'. But when I apply SVD to my image, I am not able to retrieve my original image. Is that because S matrix is not taking the all the eigen values? Eventhough, I had to get a partially correct image?

1 次查看(过去 30 天)
[u,s,v]=svd(a); ap=u*s; a=ap*v;

采纳的回答

Roger Stafford
Roger Stafford 2018-2-20
编辑:Roger Stafford 2018-2-20
You've left off the transpose operator at the last step:
ap*v';
It's a very small character, but it's all-important!
Round-off errors may cause tiny differences between your original a and the restored a. If the image pixels in the original a were all integers, just do a round on the result and that should restore it exactly.

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Eigenvalues 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by