get the table from uitable into a matrix A
显示 更早的评论
tableData = get(handles.uitable1, 'Data')
tableData =
'99' [41]
'77' [13]
can i convert it to a normal matrix so i can do a function on it
5 个评论
Pawel Jastrzebski
2018-2-21
Guillaume
2018-2-21
table2array has nothing to do with uitable. It certainly won't know what to do with a cell array.
Pawel Jastrzebski
2018-2-21
编辑：Pawel Jastrzebski
2018-2-21
If I understood the code correctly:
tableData % returns a cell
Having recreated this cell, array2table seem to covert the cell to the table:
a = {'99' '77'} % cell
b = [41 13] % double
b = num2cell(b) % double to cell
tableData = [a' b'] % cell concatenation
t = array2table(tableData) % cell to table
The output:
t =
2×2 table
tableData1 tableData2
__________ __________
'99' [41]
'77' [13]
However, like you said, it doesn't make any sense to have the number stored as a char in the first place.
Walter Roberson
2018-2-21
Do you want the '99' to be converted to numeric so that you end up with a purely numeric array?
Amjad Green
2018-2-21
采纳的回答
Your uitable returns a cell array because you've defined the first column as char. If your uitable is supposed to contain numbers only then the easiest way to fix your problem, is to change the ColumnFormat of that first column to 'numeric'. If you show us the line(s) where you create that uitable we can give you the exact syntax.
Alternatively, it can be fixed after the fact, but it'll be slower and kind of pointless:
tableData = get(handles.uitable1, 'Data');
tableData = [str2double(tableData(:, 1)), cell2mat(tableData(:, 2))];
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