How to make array with first values of matrix

2 次查看(过去 30 天)
Hello to all,
I have a matrix for example like this: [1 2 3 4 5 6 7 8 9 10;2 2 3 3 4 5 5 2 3 3]' the first column represents time, the second ID of time. I need to make a cycle which goes through the matrix and takes the first time value from the group of ID of time.
So in this case the result will be: [1 3 5 6 8 9].
unique function is unfortunately not helpful in this case because the groups of ID of time might repeat.
Thank you very much
Filip

回答(1 个)

C.J. Harris
C.J. Harris 2018-2-22
% Input
A = [1 2 3 4 5 6 7 8 9 10;2 2 3 3 4 5 5 2 3 3]';
% Result
B = A([boolean(1); diff(A(:,2))~=0],1);

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