Passing an integral function into another function that I wrote
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I want to write a function called 'HW1A' that will take in the variables tau, I_max, and V_in. V_in would be another mathematical function in itself.
Basically I want to solve V_out using the equation V_out = 1/tau * [the integral of V_in with respect to time from 0 to t_f]. V_in should be an input to the function.
function V_out = HW1A(tau,I_max, V_in);
t_f = 1.5;
fun = V_in;
V_out = 1/tau * integral(fun, 0, t_f) ;
R = V_in / I_max;
C = tau / R;
plot(t, V_out);
title(['$ V_{out} $ for RC circuit $ (R=' num2str(R) '\Omega, C=' num2str(C) 'F) $ '], 'interpreter', 'latex');
xlabel('Time (sec)', 'interpreter', 'latex');
ylabel('$ V_{out} $ (V)', 'interpreter', 'latex');
grid on
Can someone tell me what I am doing wrong?
Thanks in advance!
7 个评论
positron96
2018-2-26
It gave me this error
Walter Roberson
2018-2-26
Note that V_in needs to accept a vector of input values and to give results for each of the inputs.
positron96
2018-2-26
Walter Roberson
2018-2-26
You posted that, "V_in would be another mathematical function in itself."
but in that input position, you passed 10, which is not a mathematical function.
If for some odd reason you really did intend to pass in the function which gives the constant output 10 no matter what the input, then you would call
HW1A(0.3, 0.001, @(x) 10 * ones(size(x)) )
positron96
2018-2-26
Walter Roberson
2018-2-26
"would I have to change the third argument each time?"
Yes.
An example of a step function would be @(x) floor(x/10)
An example of a triangle function would be @(x) abs(mod(x,4)-2)-1
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