Syntax for a relational statement within a loop

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Yunus Harmanci
Yunus Harmanci 2012-5-15
Hello everyone,
I would consider myself to be an "intermediate" level matlab user, however I have come across a problem that drives me absolute mad!!
I have a formula that has two different formulations(depends on some parameters) and this formula is within a loop. I do not know how to write the statement and the loop index together.. here is the part of the code.
Kind regards,
Yunus
for dd=1:size((F_LE),2)-1
#some other stuff that works
%This is the general formulation
del_F_Lk_BL(dd) = sqrt(bf^2*tau_L1*s_L0*Ef*t + (F_LE(dd))^2) - F_LE(dd);
%This one is going to be the formulation only if *F_LE(dd) <= F_Lk_BL_D* and should somehow be written in the left hand side of the below formula:
del_F_Lk_BL(dd) = del_F_Lk_BL_G - (del_F_Lk_BL_G - del_F_Lk_BL_D)/del_F_Lk_BL_D*F_LE(dd);
end
Again, than you very much!!

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回答（1 个）

Walter Roberson
Walter Roberson 2012-5-15
You do not need anything fancy at all, as you are looping over individual dd.
for dd=1:size((F_LE),2)-1
#some other stuff that works
if F_LE(dd) <= F_Lk_BL_D
del_F_Lk_BL(dd) = del_F_Lk_BL_G - (del_F_Lk_BL_G - del_F_Lk_BL_D)/del_F_Lk_BL_D*F_LE(dd);
else
del_F_Lk_BL(dd) = sqrt(bf^2*tau_L1*s_L0*Ef*t + (F_LE(dd))^2) - F_LE(dd);
end
end
  1 个评论
Yunus Harmanci
Yunus Harmanci 2012-5-15
Thank you very much Walter, apparently I was too posh to do a basic if statement. :) That solved my problem, thanks!

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