The expression to the left of the equals sign is not a valid target for an assignment.

Question

sairohith mudduluru 2018-2-28

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/385565-the-expression-to-the-left-of-the-equals-sign-is-not-a-valid-target-for-an-assignment

编辑： Walter Roberson 2018-3-1

function[engtq_Nm,fuelrate_kgps]=calcengtq(xx,yy,zz,engpw_w,speed)
gearratio=[3.38,1.76,1.18,0.89,0.70,0.58];
engspeeds=speed./gearratio;
engtq_Nm=(engpw_w*30)./(pi.*engspeeds);
for i=1:1:6
fuelrategm/kwh(i)= interp2(xx,yy,zz,engspeeds(i),engtq_Nm(i));
end
fuelrate_kgps=fuelrategm/kwh.*engpw_w/36e8;

end

its giving me the error in line6. please help me with this

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Answer 1

SvB 2018-2-28

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https://ww2.mathworks.cn/matlabcentral/answers/385565-the-expression-to-the-left-of-the-equals-sign-is-not-a-valid-target-for-an-assignment#answer_307733

在 MATLAB Online 中打开

If I'm right, line 6 refers to this line of code:

fuelrategm/kwh(i)= interp2(xx,yy,zz,engspeeds(i),engtq_Nm(i));

You're trying to assign the result of interp2(xx,yy,zz,engspeeds(i),engtq_Nm(i)) to a variable called fuelrategm/kwh. Matlab doesn't see this as a single variable, but interprets it as fuelrategm divided by kwh. To the left of the equal sign, you should just have a single variable.

Try renaming it to fuelrategm_kwh, and you should be fine.