The expression to the left of the equals sign is not a valid target for an assignment.

2 次查看（过去 30 天）
sairohith mudduluru
编辑： Walter Roberson 2018-3-1
function[engtq_Nm,fuelrate_kgps]=calcengtq(xx,yy,zz,engpw_w,speed)
gearratio=[3.38,1.76,1.18,0.89,0.70,0.58];
engspeeds=speed./gearratio;
engtq_Nm=(engpw_w*30)./(pi.*engspeeds);
for i=1:1:6
fuelrategm/kwh(i)= interp2(xx,yy,zz,engspeeds(i),engtq_Nm(i));
end
fuelrate_kgps=fuelrategm/kwh.*engpw_w/36e8;
end
its giving me the error in line6. please help me with this

请先登录，再回答此问题。

采纳的回答

SvB
SvB 2018-2-28
If I'm right, line 6 refers to this line of code:
fuelrategm/kwh(i)= interp2(xx,yy,zz,engspeeds(i),engtq_Nm(i));
You're trying to assign the result of interp2(xx,yy,zz,engspeeds(i),engtq_Nm(i)) to a variable called fuelrategm/kwh. Matlab doesn't see this as a single variable, but interprets it as fuelrategm divided by kwh. To the left of the equal sign, you should just have a single variable.
Try renaming it to fuelrategm_kwh, and you should be fine.

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 MATLAB 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by