hist within a parfor creates transparency violation error?

2018 3 1
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更新时间：2018 3 2
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This code creates a transparency violation error. Is this by design??
s = cell(2,1);
s{1} = randn(100);
s{2} = randn(100);
parfor i=1:2
figure(i);
y = s{i};
hist(y);
end

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Edric Ellis
Edric Ellis 2018-3-2
编辑：Edric Ellis 2018-3-2

0 个投票

hist internally uses inputname to support additional functionality in the resulting plot. Unfortunately, using inputname in a function called from parfor results in the transparency violation error you're seeing. You can work around this by ensuring that the input to hist doesn't have a name (i.e. it's a temporary):
parfor i=1:2
figure(i);
y = s{i};
hist(1 .* y);
% hist(s{i}) also works
end

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