What does the following MATLAB code do?
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>> x=7.123456789;
>> n=7;
>> delta=0.5;
>> r=x*10^n+delta;
>> r=fix(r);
>> r=r/10^n;
>> disp(r)
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Star Strider
2018-3-4
It takes ‘x’, raises it to the ‘n’-th power, adds ‘delta’ to it, then rounds that result toward zero, divides that result by ‘10^n’ and prints the result.
The intent appears to be to round ‘x’ to 7 decimal places.
You can do that easily with the current version of the round function:
r = round(x, 7)
that will produce the same result.
1 个评论
Walter Roberson
2018-3-4
I noticed that it does not do the same thing as round(x,n) for negative numbers.
>> fix(-pi*100000+0.5)/100000
ans =
-3.14158
>> round(-pi,5)
ans =
-3.14159
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