how to find Place on non zero values in matrix?

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Tha saliem
Tha saliem 2018-3-5
评论： Tha saliem 2018-3-5
hey all
i need to find places of 1's in matrix A:
A = [0,0,0,1,0,0,1,1,0;0,0,1,0,0,0,0,0,1;0,0,0,0,1,0,0,0,0]
result = {[4,7,8];[3,9];5}
please help

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采纳的回答

Stephen23
Stephen23 2018-3-5
编辑：Stephen23 2018-3-5
>> A = [0,0,0,1,0,0,1,1,0;0,0,1,0,0,0,0,0,1;0,0,0,0,1,0,0,0,0];
>> [R,C] = find(A);
>> X = accumarray(R,C,[],@(v){v.'});
>> X{:}
ans =
4 7 8
ans =
3 9
ans =
5

更多回答（2 个）

javad ebrahimi
javad ebrahimi 2018-3-5
HI dear Tha saliem
I hope that I have been able to understand what you mean, and the following code can help you
clc;clear;close all
A = [0,0,0,1,0,0,1,1,0;0,0,1,0,0,0,0,0,1;0,0,0,0,1,0,0,0,0];
B=find(A~=0)
size=size(A)
[Row,Col]=ind2sub(size,B)
result={Col(Row==1),Col(Row==2),Col(Row==3)}
Jan
Jan 2018-3-5
A = [0,0,0,1,0,0,1,1,0;0,0,1,0,0,0,0,0,1;0,0,0,0,1,0,0,0,0]
result = cellfun(@find, num2cell(A, 2), 'UniformOutput', 0)

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