Cell contents reference from a non-cell array object?

2018 3 6
2 个回答
更新时间：2018 3 7
8 次查看（30 天）

0 个投票

function [ information ] = printInfo( subjects )
s=height(struct2table(subjects));
for x=1:s
name=subjects(x).name;
weight=subjects(x).weight;
maxweight=max(weight);
feet=subjects(x).height.feet;
inches=subjects(x).height.inches;
str='%d: %d''%d", %d pounds';
information=sprintf(str,name,feet,inches,maxweight);
end
end

4 个评论
显示 2更早的评论 隐藏 2更早的评论

Birdman
Birdman 2018-3-6
What is your input to the function?
Garrett Miller
Garrett Miller 2018-3-6
编辑：per isakson 2018-3-6
It is a struct array that has a varying amount of subsets, hence the first line of code
s=height(struct2table(subjects));
Walter Roberson
Walter Roberson 2018-3-6
Which line is the error occurring on?
You should probably be replacing the assignment to s with
s = numel(subjects);
Garrett Miller
Garrett Miller 2018-3-6
编辑：per isakson 2018-3-6
That's kind of the issue, it occurs on the .gui code that I am supposed to be using to check the functionality
clear subjects;
subjects.name = char( randi( 26 , 1 , randi( 10 ) ) + 96 );
subjects.id = randi( 100 );
subjects.weight = randi( 100 , 1 , 2 ) + 100;
subjects.height.feet = randi( 4 ) + 3;
subjects.height.inches = randi( 12 ) - 1;
for s = 2 : randi( 10 )
subjects( s ).name = char( randi( 26 , 1 , randi( 10 ) ) + 96 );
subjects( s ).id = randi( 100 );
subjects( s ).weight = randi( 100 , 1 , 2 ) + 100;
subjects( s ).height.feet = randi( 4 ) + 3;
subjects( s ).height.inches = randi( 12 ) - 1;
end
yourInfo = printInfo( subjects );
for string = 1 : length( yourInfo )
y = 1 - string / length( yourInfo );
uicontrol( 'style' , 'text' , 'units' , 'normalized' , ...
'fontunits' , 'normalized' , ...
'fontname' , 'fixedwidth' , 'string' , ...
yourInfo{ string } , ...
'position' , [ 0 y 1 1 / length( yourInfo ) ] );
end
The error is on yourInfo{ string } , ...

请先登录，再进行评论。

请先登录，再回答此问题。

回答（2 个）

per isakson
per isakson 2018-3-6
编辑：per isakson 2018-3-6

0 个投票

yourInfo is a character array, not a cell array, thus replace
yourInfo{ string }
by
yourInfo( string )
After done that correction your code produces a plot and no errors.
btw: string is a poor name of a loop-variable - IMO
Walter Roberson
Walter Roberson 2018-3-7
编辑：Walter Roberson 2018-3-7

0 个投票

function [ information ] = printInfo( subjects )
s=numel(subjects);
for x=1:s
name=subjects(x).name;
weight=subjects(x).weight;
maxweight=max(weight);
feet=subjects(x).height.feet;
inches=subjects(x).height.inches;
str='%s: %d''%d", %d pounds';
information{x}=sprintf(str,name,feet,inches,maxweight);
end
end

类别

在 帮助中心 和 File Exchange 中查找有关 Characters and Strings 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by