How to compare 3 different arrays

Question

skysky2000 2018-3-7

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/386971-how-to-compare-3-different-arrays

评论： Walter Roberson 2018-3-28

Dear All,

I have 3 arrays as shown below (A, L1, E), First, I need to check array A, in each column the similar number and then take the location of each similar number. Then, when I found there are number same in each column , I move to array L1 and compare to locations of the similar number and take the highest location number = 1. In case if the locations in array L1 same as well, then I need to go to the array E and compare the locations of highest number and give it value 1.

A=[22  40  55  72;
33  55  32  67;
45  40  23  65;
22  40  55  45
];
L1=[3  5  60  3;
2  7  6  43;
5  5  45  56;
3  5  55  34
];
E=[0.52  0.3  0.7  0.45;
0.2  0.11  0.6  0.2;
0.1  0.32  0.45  0.33;
0.51  0.31  0.79  0.2
];

the expected results should be:

matrix=[1  0  0  1;
1  1  1  1;
1  1  1  1;
0  1  1  1
];

Help please , I have stuck with this problem since week. Please admin, I appreciate if you dont locked the question, its not part of assignment.

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Walter Roberson 2018-3-7

In column 2, the 55 in the second row is unique, so matrix(2,2) = 1.

In column 2, the 40 in rows 1, 3, 4 are the same, so for those we have to look in column 2 row 1, 3, 4 of L1. We see 5 for all of those entries there, so we have to look in E. The corresponding entries in E are 0.3, 0.32, 0.31, the highest of which is 0.32 from row 3. So matrix(2,3) = 1. But that means that neither (2,1) nor (2,4) are highest under those rules, so matrix(2,1)=0 and matrix(2,4)=0.

That would leave us with matrix(:,2) = [0; 1; 1; 0]. But your requested output is [0; 1; 1; 1] there.

Did I misunderstand the rules, or is your expected result incorrect?

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Answer 1

skysky2000 2018-3-7

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/386971-how-to-compare-3-different-arrays#answer_308932

Thanks Walter for your replying. in array L1 we put 0 into location of highest number , but in array E we put 0 in the miniumun valuve. so, the results as below: results = [1 1 1 0; 0 1 1 1; 0 1 1 1;1 1 1 1].

I can share the code if you like.