Matrix-con​catenation​-generated c/c++ code is incompatible with MATLAB

2018 3 8
2 个回答
更新时间：2018 3 8
5 次查看（30 天）

0 个投票

Hello,
I did the following:
A = [0 1;1 0];
B = [1;2];
C = [A B];
then I generated a c++ code that calculates C. Matlab yields:
C = [0 1 1;1 0 2];
while c++ yields different result namely:
C = [0 1;1 0;1 2];
Does anybody know the reason for this incompatibility? Any suggestion how to overcome this problem?
Best regards,
Mohamed

请先登录，再回答此问题。

回答（2 个）

Walter Roberson
Walter Roberson 2018-3-8

0 个投票

while c++ yields different result namely:
C = [0 1;1 0;1 2];
Does it? Remember in C and C++ matrices are indexed across first rather than down like in MATLAB, so in MATLAB a 2 x 3 array C has C(1,1) directly before C(2,1) in memory. To replicate the in-memory order in C++ would involve double C[3][2]
Ichaoui
Ichaoui 2018-3-8

0 个投票

Thanks for your answer,
but I think my example was a little bit confusing and does not show the problem I'm facing. Because A is symmetric one would think it is just a matter of Transposition. Here another is example:
A = [1 2;3 4];
B = [5;6];
C = [A B];
with the in c++ generated function I get (as an array not as a matrix)
C = [1 2;3 4;5 6];
or just as an array
1 2 3 4 5 6
rather than
C = [1 2 5;3 4 6];
thanks,
Mohamed

类别

在 帮助中心 和 File Exchange 中查找有关 Logical 的更多信息

标签

提问:

Ichaoui
Ichaoui
2018-3-8

回答：

Ichaoui
Ichaoui
2018-3-8

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by