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Solve function

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lina
lina 2012-5-18
Hi Everyone,
I need to find the value of xgaris1
dis1=1.5;
newx=3;
newy=2;
xgaris1= solve('dis1^2=abs(sqrt(xgaris1-newx)^2+((3-xgaris1)-newy)^2)');
but the output of xgaris1 always didn't calculate the numeric value of dis1, newx, and newy as seen below: xgaris1 = (4*dis1^2 + 4*newx + 4*newy - 11)^(1/2)/2 - newy + 5/2 5/2 - (4*dis1^2 + 4*newx + 4*newy - 11)^(1/2)/2 - newy
For any reply, will very appreciate.
Thanks in advance, Lina

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采纳的回答

Walter Roberson
Walter Roberson 2012-5-18
Convert solve('A=B') to solve((A)-(B)) with no quotes. But
syms xgaris1
first.
  2 个评论
lina
lina 2012-5-18
Hi Walter,
thanks for the reply..
I've tried as your suggestion, but have some errors below :
>> clear
dis1=1.5;
newx=3;
newy=2; syms xgaris1;
solve((dis1^2)=(abs(sqrt(xgaris1-newx)^2+((3-xgaris1)-newy)^2)))
solve((dis1^2)=(abs(sqrt(xgaris1-newx)^2+((3-xgaris1)-newy)^2)))
|
Error: The expression to the left of the equals sign is not a valid
target for an assignment.
>> clear
dis1=1.5;
newx=3;
newy=2; syms xgaris1;
xgaris1=solve((dis1^2)=(abs(sqrt(xgaris1-newx)^2+((3-xgaris1)-newy)^2)))
xgaris1=solve((dis1^2)=(abs(sqrt(xgaris1-newx)^2+((3-xgaris1)-newy)^2)))
|
Error: The expression to the left of the equals sign is not a valid
target for an assignment.
Walter Roberson
Walter Roberson 2012-5-18
(A) MINUS (B)

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