How to find minimal distance between elements?
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I have a vector, and I would like to find the minimal distance between element values. Any element distance from any element in the set. Is it possible to do this without a for cycle?
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Image Analyst
2018-3-10
Mr. M, you've now asked 311 questions and "Accepted" virtually none of them. Perhaps now you can "thank" the people who took their time to try to help you by Accepting their answers so that they get reputation points. That's the etiquette in this forum. Thanks in advance.
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Roger Stafford
2018-3-9
编辑:Roger Stafford
2018-3-9
Let your vector be called v. Then do this:
d = min(diff(sort(v)));
This finds the minimum distance between any two elements of v, but it does not show the points in v where that occurs. To do that requires the use of the index returned as a second output of the 'sort' function as well as an index from the 'min' function. Let us know if that is what you want.
2 个评论
Guillaume
2018-3-9
Indeed, as long as we're talking about a vector of numbers, this is the most efficient. To get the original indices of the two closest numbers:
v = randi(1000, 1, 10) %demo data
[sorted, originalidx] = sort(v);
[mindistance, where] = min(diff(sorted));
closestindex = originalidx([where, where+1]);
fprintf('elements at index %d and %d have got the minimum distance of %d\n', closestindex, mindistance)
更多回答(5 个)
Jos (10584)
2018-3-9
Without creating a possibly large intermediate N-ny-N matrix or using a possibly slow sort
V = [1 8 6 4 2 10] ;
W = nchoose2(V) % all pairs of distinct elements
D = abs(W(:,2)-W(:,1)) % distance between pairs
[minD, ix] = min(D) % minD = 1
minPair = W(ix,:) % minPair = [1 2]
nchoose2 is a fast function to get all combinations of two elements, and can be downloaded from the Matlab File Exchange: https://uk.mathworks.com/matlabcentral/fileexchange/20144-nchoose2-x-
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Image Analyst
2018-3-9
If the "vector" is actually a matrix of (x,y) locations, you can use pdist2(). Let me know if that's the case and I'll give you an example.
3 个评论
Image Analyst
2021-1-29
numPoints = 7;
xy1 = rand(numPoints, 2);
xy2 = rand(numPoints, 2);
distances = pdist2(xy1, xy2);
% Set 0's to inf since we don't want to find the min
% distance of a point to itself, which is 0.
distances(distances==0) = inf
% Find min distance
minDistance = min(distances(:))
% Find row and column where it occurs.
[row1, row2] = find(distances == minDistance)
% Plot all points
plot(xy1(:, 1), xy1(:, 2), 'r.', 'MarkerSize', 30); % Plot set 1.
hold on;
plot(xy2(:, 1), xy2(:, 2), 'b.', 'MarkerSize', 30); % Plot set 1.
% Plot the line
x1 = xy1(row1, 1);
y1 = xy1(row1, 2);
x2 = xy2(row2, 1);
y2 = xy2(row2, 2);
plot([x1, x2], [y1, y2], 'k-', 'LineWidth', 2);
grid on;
legend('Set 1', 'Set 2', 'Closest Pair');
caption = sprintf('Min Distance = %.4f', minDistance);
title(caption, 'fontSize', 20);
Please vote for my Answer if it helped you.
Von Duesenberg
2018-3-9
This will get you started:
dumVect = [1 3 5 30]';
[minVal, idxMin] = min(diff(dumVect))
If you work with more dimensions, you may want to use pdist instead of diff. And of course, I'll let you figure out how you want to handle ties.
2 个评论
Jan
2018-3-9
编辑:Jan
2018-3-10
n = 10;
v = rand(1, n);
dist = abs(v - v.'); % Auto-expand since R2016b
dist(1:(n+1):end) = Inf; % Mask the zeros [EDITED]
% dist = bsxfun(@minus, v, v.') .^ 2; % For older versions
[minValue, minIndex] = min(dist(:));
4 个评论
Jan
2018-3-15
@Mr M.: You can simply try it.
v = rand(2,3)
v.'
It is the transpose operator. The quote without the dot before replies the conjugate complex value in addition.
Jos (10584)
2018-3-9
编辑:Jos (10584)
2018-3-9
By definition the minimum distance is zero because v(i)==v(i) for any element i of the vector v.
But I assume you want the minimum distance between v(i) and v(j) for all pairs (i,j) where i is unequal to j, but forgot to mention that ... :p
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