How can I create an array with a for loop?
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Hi I’m trying to create an array of values that are output from a function. The function goes from -20 to 50 but I can’t create an array that large so I’m confused on what to do. The attached picture is what I have so far and it’s not working.
% code
clear all;
close all;
A = zeros(1:70);
for m = 1:70;
n = -50:20;
X = power(0.8,n)
A(m) = X
end
stem(n,arrayofA(n))
1 个评论
Stephen23
2018-3-12
Do not use the accepted answer: a loop is NOT required:
n = -50:20;
A = power(0.8,n);
回答（2 个）
Torsten
2018-3-12
A = zeros(1,71);
n = -50:20;
A = power(0.8,n)
1 个评论
Jos (10584)
2018-3-12
This is preferred over the solution with a for-loop. However, there is no need to initialise A with zeros first, since you overwrite it at the third line.
Try this:
A=zeros(1,70);n=-50:20;
for m=1:numel(n)
A(m)=power(0.8,n(m));
end
stem(n,A)
5 个评论
Paige Coffeen
2018-3-12
Birdman
2018-3-12
It is the condition for the loop to be operated. m starts at 1, incremented by 1 and the loop is over when m is equal to the number of elements in n vector, which is 71. At each step, the statement in for loop is executed and the result is stored in A array.
Jos (10584)
2018-3-12
As Torsten showed, A = power(0.8,n) would do. No need for a for-loop
y = zeros(1,12);
for i = 1:12
y(i+1) = y(i) + ((5 - (4/50)*y(i)));
end
y
x = zeros(1,10);
for i = 10:-1:2
x(i-1) = x(i) + ((5 + (4/50)*x(i)));
end
x
Good Day,
May I ask how can I insert the start and stop variable on above code? for example I want to start in 17 to 30 or 15 to 2 with decrementing step.
Thanks and Regards,
Dennis
Walter Roberson
2021-8-24
You should ask your own question for that.
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2018-3-12
2021-8-24
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