How to convert string to number and process underscores? (e.g. '57_77_' to 57.77)

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How do you convert a string with underscores to a number, namely '57_77_' to 57.77? What commands would you use?
I am looking through the documentation, e.g. join, compose, sprintf, extractBefore, trying to figure out how to process such a string, namely to execute the steps:
  1. delete final '_'
  2. convert '_' to decimal point '.'
  3. convert string to number

采纳的回答

Stephen23
Stephen23 2018-3-14
编辑:Stephen23 2018-3-14
Faster and more efficient than using str2num (which hides a slow eval call inside) is to simply use the low-level function sscanf:
>> sscanf(strrep('57_77_','_','.'),'%f')
ans = 57.770
This is ten times faster than the accepted answer (1e4 iterations):
Elapsed time is 0.277028 seconds. % my code
Elapsed time is 2.63426 seconds. % accepted answer
  5 个评论
Stephen23
Stephen23 2018-3-14
If the CSV files all have the exactly same format then there is no reason why detectImportOptions has to be called 40 times. Why not move it out of the function, call it once before the loop, and pass that data as an input argument?
Daniel Bridges
Daniel Bridges 2018-3-15
The goal is to read the table variable names in each file: Their order, number, and name differ. So I was thinking I needed to call it each time since the variable names generally differ each time.
Isn't there a better command than detectImportOptions since .VariableNames is all I need?

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更多回答(3 个)

Birdman
Birdman 2018-3-14
编辑:Birdman 2018-3-14
The wise thing would be to first convert underlines to dots by using regexprep or strrep:
a=regexprep(a,'_','.')
or
a=strrep(a,'_','.')
and then delete the last character by
a(end)=[]
a=str2num(a)
Other way would be doing this by using regexp:
idx=regexp(a,'_')
a(idx)=['.',' ']
a=str2num(a)

Jos (10584)
Jos (10584) 2018-3-14
all in one go:
a = '12_23_'
v = str2num(strrep(a(1:end-1), '_', '.'))

Daniel Bridges
Daniel Bridges 2018-3-14
编辑:Daniel Bridges 2018-3-14
Here is one method that works, but I am not happy using a cell wrapper just to use Walter Roberson's cellfun; I'm sure there's a better way ...
volume = '57_77_';
volume = cellfun(@(S) S(1:end-1), {volume}, 'Uniform', 0);
volume = volume{1};
volume = regexprep(volume,'_','.');
volume = str2num(volume)
Result:
volume =
57.7700
  4 个评论
Daniel Bridges
Daniel Bridges 2018-3-14
编辑:Daniel Bridges 2018-3-14
Oh! Sorry for my awkward question -- I accidentally combined Japanese and English grammar. (or else made a Japanese-type English grammar mistake) I will edit my question to clarify, too, if not simply for the sake of English.

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