Index exceeds matrix dimensions.

2018 3 14
1 个回答
回答已采纳
更新时间：2018 3 14
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0 个投票

*Y=2;
g=[20,10];
w=40 : -2 : 3;
for x=1:length(w)
if w(x)<=5 "why get I problem here, its says 'Index exceeds matrix dimensions'"
break
else
w=setdiff(w(w>(5)),g);
A= x*3;
w1=A.*Y;
end
end*

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 采纳的回答

Birdman
Birdman 2018-3-14
编辑：Birdman 2018-3-14

0 个投票

Because at the following line
w=setdiff(w(w>(5)),g)
your w vector becomes a 16 element array when x=1 and when x=17, you try to reach 17th element of your w array, which is not possible.
If you put a counter to your loop named cnt as follows, you will see the reason actually:
Y=2;
g=[20,10];
w=40 : -2 : 3;
cnt=0;
for x=1:length(w)
cnt=cnt+1;
if w(x)<=5 "why get I problem here, its says 'Index exceeds matrix dimensions'"
break
else
w=setdiff(w(w>(5)),g);
A= x*3;
w1=A.*Y;
end
end
When the loop is broken, the value of cnt is 17.

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silvano carvalho
silvano carvalho 2018-3-14
Y=2;
g=[20,10];
w=40 : -2 : 3;
for x=1:length(w)
if w(x)<=5
break
else
w=setdiff(w(w>(5)),g); > I JUST WANNA w to SKIP THE VALUES OF g. HELP!
A= x*3;
w1=A.*Y;
end
end
Birdman
Birdman 2018-3-14
编辑：Birdman 2018-3-14
Ok, you don't need to do it in the loop, because you overwrite w at the very first step and actually that line is just a waste of time until loop is broken. You get rid of g values at the first step. You may do it outside the loop.
silvano carvalho
silvano carvalho 2018-3-14
Birdman allways saves
Birdman
Birdman 2018-3-14
Haha, you are welcome :)

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