Divide a matrix with an array along a specific dimension

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ANKUR KUMAR
ANKUR KUMAR 2018-3-16
评论： Beata Opacka 2020-3-26
A=rand(10,20,30);
B=[1:30];
I want to divide A with B along the third dimension. I got the required result using loop.
for ii=1:30
C(:,:,ii)=A(:,:,ii)/B(ii);
end
But is there any pre-defined function which does the same operation, which takes the dimension as a input along which we want to divide a matrix.

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采纳的回答

Stephen23
Stephen23 2018-3-16
编辑：Stephen23 2018-3-16
Once you make the sizes compatible you can do this using standard methods without any loop. Use permute or reshape to get the correct size of B. For example In R2016b and later a standard rdivide will do this:
A ./ reshape(B,1,1,[])
or for earlier versions use bsxfun:
bsxfun(@rdivide,A,reshape(B,1,1,[]))

更多回答（1 个）

Akira Agata
Akira Agata 2018-3-16
How about using arrayfun ?
C = arrayfun(@(k) A(:,:,k)./B(k), 1:30,'UniformOutput',false);
C = cat(3,C{:});

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