0 个投票

how can i integral a function which was written in matlab but there is wrong , i dont no where it is :
syms tau
syms y
f= @(y,tau)y*exp(-0.5.*y.^2/ tau)
expecty=integral2(f, -2,4,0,Inf,'auto')

请先登录，再回答此问题。

 采纳的回答

Birdman
Birdman 2018-3-16

1 个投票

integral2 is defined for function handle, therefore you do not need symbolic variables:
f= @(y,tau)y.*exp(-0.5.*y.^2./ tau)
expecty=integral2(f, -2,4,0,Inf,'auto')

6 个评论
显示 4更早的评论 隐藏 4更早的评论

elham kreem
elham kreem 2018-3-16
if i use it as a defined , the result is:
expecty =
NaN
Torsten
Torsten 2018-3-16
The result is correct.
Did you expect something finite for the integral ?
elham kreem
elham kreem 2018-3-16
do you mean that :
expecty = nan
is correct?
Steven Lord
Steven Lord 2018-3-16
When y = 0 and tau = 0, you're computing 0.*exp(0./0). 0./0 is NaN, exp(NaN) is NaN, and 0*NaN is NaN. Once NaN enters a calculation, it tends to propagate throughout that calculation.
Torsten
Torsten 2018-3-16
Neglecting numerical aspects like division by 0, your integral is +Inf.
Best wishes
Torsten.
elham kreem
elham kreem 2018-3-16
gentelmen , thanks for your answers , but there is something wrong?
because the result is not convincing .
if i integrate the function with syms y and tau , are the code right and the result?
syms tau
syms y
fun = @(y,tau) (1/tau) * y * exp((-0.5*y^2 / tau)
f1 = int(fun , y ,tau )
is this mean double integral , for y and tau?
the result is
exp(-y^2/(2*tau)) - exp(-tau/2)
is the result convincing?

请先登录，再进行评论。

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Calculus 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by