Solving equation with increasing value by multiplication
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Hello, I am trying to create a code to calculate the area of a triangle with a range of length. And these length number are twice the previous number. Basically, first is 2, then 4, 8, 16, 32, 64, 128. Its breadth stays the same.
Code.
a =[1:???:128]
for i=1:length(a)
y=a(i)*100/2
end
I appreciate all your help in advance.
回答（2 个）
James Tursa
2018-3-16
a = 2.^(1:7);
Faith Bagire
2020-9-4
The best way that worked for me is using a while loop!
a=1;
while a < 128
y=a*100/2
a=a*2;
end
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2018-3-16
2020-9-4
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