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I want to know the cell number i.e. row and column of the matrix, whichever is above 10% of the normal vlaue. and i also want to get the values in the cell.

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Parul Tewatia
Parul Tewatia 2018-3-19
回答： Jos (10584) 2018-3-22
Hi I have a matrix with 338 rows and 210 columns.
I want to know the cell number i.e. row and column of the matrix, whichever is above 10% of the normal value. and i also want to get the values in the cell.
the code i have written TBS_down=AUC_final_TBS_down
TBS_down(abs(TBS_down)<0.1)=0; [I,J]=find(abs(TBS_down)>0);
it is just to find all values above 0.1 but i also need to get the row and column i.e. I and J (which correspond to certain parameters) values and also the value in the corresponding cell so i dont have to look manually. Help would be so great. Thanks

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采纳的回答

Venkata Siva Krishna Madala
Hello Parul,
You are doing the extraction of the row and column number properly. However, to get the value in the cell you can do any of the following
extracted_values=TBS_down(I,J)
extracted_values=AUC_final_TBS_down(I,J)
If you want the row, column, and the value then you can probably iterate as shown below and put the elements into a cell array.
c={}
temp=[I,J]
for i=1:size(temp,1)
c{i}=[temp(i,1) temp(j,1) TBS_down(temp(i,1),temp(j,1))];
end
Regards,
Krishna Madala

更多回答（1 个）

Jos (10584)
Jos (10584) 2018-3-22
I am unsure if I understand your question completely, but here is my 2p:
X = rand(4,3) % example data
TF = X > 0.1
[rownum, colnum] = find(TF)
value = X(TF)

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