Issue with mean function
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Hi,
I am wanting to make each element in an array (excluding the first and last rows & columns, i.e. the elements on the edge) the average of that element and the 8 surrounding elements using the mean() function. The mean function is currently returning a 1x125 matrix where each element is the average of the elements in each corresponding column in the original 125x125 matrix. Is there a way I can make the mean function return a 125x125 matrix (the same size as the original matrix to be averaged)? It's for a uni assessment and we're supposed to use the mean function.
Cheers, Bruce
1 个评论
Daniel Shub
2012-5-21
Although by a different user, this is a duplicate of http://www.mathworks.com/matlabcentral/answers/38766-averaging-matrix-and-store-it-in-a-new-matrix
回答（2 个）
Titus Edelhofer
2012-5-21
0 个投票
You will need to do exactly what you are describing: taking for each element the mean of the surrounding elements. What you did was to compute the mean of the entire matrix ...
Titus
Sean de Wolski
2012-5-21
Sure, you could do this with mean() and a couple of for-loops but conv2() is way cooler:
xm3x3 = conv2(x,ones(3)*mean([0 1/9 2/9]),'same');
2 个评论
Image Analyst
2012-5-21
Of course he has conflicting requirements. "(excluding the first and last rows & columns, i.e. the elements on the edge) " means that he want the 'valid' option of conv2(), while "(the same size as the original matrix..." means that he wants the 'same' option of conv2().
Sean de Wolski
2012-5-21
I saw that. When in doubt, go same, it's easier to extract than create.
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