Sort rows based on number of 1's in each row.

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Ananya Malik
Ananya Malik 2018-3-20
评论： Ananya Malik 2018-3-20
I have a matrix A = [1 1 0 1; 1 0 0 0 ; 1 0 1 0 ; 1 1 1 1]; I count the number of 1's in each row and I get count=[3 1 2 4]. I want to get A' = [1 1 1 1; 1 1 0 1; 1 0 1 0; 1 0 0 0]; How to get it. TIA.

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Stephen23
Stephen23 2018-3-20
编辑：Stephen23 2018-3-20
>> A = [1,1,0,1;1,0,0,0;1,0,1,0;1,1,1,1];
>> [~,idx] = sort(sum(A,2),'descend');
>> A(idx,:)
ans =
1 1 1 1
1 1 0 1
1 0 1 0
1 0 0 0

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