how to convert decimal to binary ?

I have vector of integer values : y = [ 1 2 3 4 5 ... 998 999 1000 ] , how can i generate binary random numbers with the same length for lower and upper of vector y ( i.e the binary value of 1000 is (0 0 0 1 0 1 1 1 1 1), and the binary value of 2 is ( 1 0 0 0 0 0 0 0 0 0 ) and so on .. This is the code y = [ 1 : 1000 ]; empty.value = []; out=repmat(empty.value,5,1);
for i = 1 : 5 % i want 5 binary numbers within the range 1 to 1000 and must be all the same length of bits a = randi(1000); b = de2bi(a); out(i).value = b ; end %% the results are different in number of bits {[1,1,1,1,1,1];[1,1,0,1,0,1,0,0,1];[1,1,1,1,0,1];[0,1,0,1,1,1,1,1,1];[0,1,0,1,1,1,1,1,0,1]}

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Stephen23
Stephen23 2018-3-21
编辑:Stephen23 2018-3-21
>> dec2bin(randi([1,1000],5,1),10)
ans =
1101100000
1000010111
1100010100
0000100001
1110110000
And to convert to numeric simply subtract '0':
dec2bin(...)-'0'

10 个评论

Thank you so much...
but this output is char i want it integer in order to convert it to decimal later
thank you very very very much...
@Ameer Kadhim: I hope that it helps. Remember to accept the answer that helped you most to resolve your question.
Thank you Stephen Cobeldick very much.. i accept your answer
I deleted mine then since this answer solves your problem.
your answer do not solve my problem and i asked several times... thank you dir , i am sorry....
@Stephen Cobeldick your answer not correct too .. see v = bi2de(dec2bin(randi([1,1000],1,1),10)-'0') v =
1013
i not want v greater than 1000 . ok (v must be less than 1000)
>> dec2bin(randi([1,1000],5,1),10)
ans =
5×10 char array
'1100101111'
'1110001010'
'0001111111'
'1110010010'
'1001111001'

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