Can someone please help me with a loop issue.
显示 更早的评论
I am trying to write a simple strain loop such that the first strain value E_1=0, and subsequent values follow with an increment of 0.02 that is delta strain between each step is 0.02, the loop I wrote is as follows:
for i=2:10
E_1=0;
E_(i)=E_(i-1)+0.02
end
but this does not work for some reason it gives an error that E_ is an undefined function. Can anyone please help me with this very simple problem.
2 个评论
E_1=0;
defines a variable named exactly E_1. Then you try to access the first element of a variable named E_ which clearly does not exist at that point. Note that E_1 is not how indexing works: it does not treat the 1 as an index, it is part of the name!
Asim Gillani
2018-3-21
回答（1 个）
David Fletcher
2018-3-21
编辑：David Fletcher
2018-3-21
E_=0:0.02:0.2
Values are indexed as E_(1), E_(2) and so on
4 个评论
Asim Gillani
2018-3-21
David Fletcher
2018-3-21
It's up to you, but I really wouldn't advise you to separate your variables like that - it's makes processing your data much, much more difficult. The code you've posted won't work in that way anyway, and I'm not in the habit of propagating bad habits, so I'll leave it up to you to amend it yourself if you really want to make them all separate variables.
James Tursa
2018-3-21
"... but I want the values to be displayed as E_1=0, E_2=0.02, E_3=0.04... "
Please don't name variables this way! There's lots of posts on this site telling you why, but just don't do it! Keep the numbers as a vector and use indexing, or if you really need separate variables for some reason (that you haven't told us), try a cell array E_{1}, E_{2}, etc.
Asim Gillani
2018-3-21
类别
在 帮助中心 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
2018-3-21
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
