Rotating a cylinder by 90 degrees

4 次查看(过去 30 天)
I've generated a cylinder as follows: [x,y,z]=cylinder([0,10,10,0],100);
z([1,2],:)=0;
z([3,4],:)=100;
mesh(x,y,z)
axis equal; I want to have the cylinder lying flat i.e. a rotation by 90d degrees. I've tried using the rotate function but couldn't get it to work, any suggestions?

采纳的回答

Star Strider
Star Strider 2018-3-23
I don’t understand what your problem with rotate is.
Try these:
[x,y,z]=cylinder([0,10,10,0],100);
z([1,2],:)=0;
z([3,4],:)=100;
figure(1)
hm = mesh(x,y,z);
rotate(hm, [1 0 0], 90)
axis equal
figure(2)
hm = mesh(x,y,z);
rotate(hm, [0 1 0], 90)
axis equal
figure(3)
hm = mesh(x,y,z);
rotate(hm, [1 1 0], 45)
axis equal
  1 个评论
Julien Cotton
Julien Cotton 2021-2-9
Those lines do not work for me : get the following error :
Error using horzcat
Dimensions of arrays being concatenated are not consistent.
Error in rotate (line 49)
tmp =r*[x(:) y(:)]';

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Interactions, Camera Views, and Lighting 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by