could anyone help me to solve this issue.

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Prabha Kumaresan
Prabha Kumaresan 2018-3-26
回答： Jan 2018-3-26
I am getting the result in the following manner
iwant =
34 12
24 13
23 14
if i use the command line
sprintf('%d',iwant) - '0'
i am getting
ans =
3 4 2 4 2 3 1 2 1 3 1 4
But i want to have the result in the following way
(3 4 1 2,2 4 1 3, 2 4 1 4)
Could anyone help me to fix this issue.
  2 个评论
Akira Agata
Akira Agata 2018-3-26
Question for clarification.
You want to convert the following numeric 1-by-6 array into the string ('3 4 1 2,2 4 1 3, 2 4 1 4') ?
iwant = [34 12 24 13 23 14];
Prabha Kumaresan
Prabha Kumaresan 2018-3-26
i want to separate 3 and 4, 1 and 2, 2 and 4 and so on. But how it can be implemented for n numbers.

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回答（3 个）

Akira Agata
Akira Agata 2018-3-26
Like this?
iwant = [34 12 24 13 23 14];
c = num2cell(erase(num2str(iwant),' '));
output = str2double(c);
In this case, the output is the following 1-by-12 numeric vector.
>> output
output =
3 4 1 2 2 4 1 3 2 3 1 4
  2 个评论
Prabha Kumaresan
Prabha Kumaresan 2018-3-26
but when i run the code i am getting errror Undefined function or variable 'erase'. Error in line c = num2cell(erase(num2str(iwant),' '))
Walter Roberson
Walter Roberson 2018-3-26
erase() requires R2016b or later.
... It would be easier to assist you if you upgraded to a recent MATLAB version.

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Walter Roberson
Walter Roberson 2018-3-26
cell2mat(cellfun(@(C) C-'0', sprintfc('%d', iwant), 'uniform', 0))
This does assume that the entries all have the same number of digits (but does not assume that the number of digits is 2)
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Walter Roberson
Walter Roberson 2018-3-26
MATLAB R2015b:
>> iwant = [ 34 12
24 13
23 14]
iwant =
34 12
24 13
23 14
>> cell2mat(cellfun(@(C) C-'0', sprintfc('%d', iwant), 'uniform', 0))
ans =
3 4 1 2
2 4 1 3
2 3 1 4
Please post a complete copy of the error message you encounter when you run the code that I posted. Not someone else's code: you said that you encountered an error running my code.

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Jan
Jan 2018-3-26
The best idea would be to create the numbers in the correct format directly. I guess, that you used a method I have suggested to one of your former questions, where it was not clear if you want "3, 4" or "34". If this is the case, simply omit the multiplication by [10; 1].
But to solve the current problem:
iwant = [34 12; 24 13; 23 14];
b = rem(iwant(:).', 10);
a = (iwant(:).' - b) / 10;
reshape(permute(reshape([a,b], [3,2,2]), [1,3,2]), 3,4)
[3 4 1 2; ...
2 4 1 3; ...
2 3 1 4];
Please note, that "(3 4 1 2,2 4 1 3, 2 4 1 4)" is not clear, because it is not a valid Matlab syntax.

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