Find length of a structure element and remove them according to length?

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Arif Ahmed
Arif Ahmed 2018-3-26
回答： Arif Ahmed 2018-3-27
If I have a structure "output" with a field "output.I".
How can I check the lengths of all the output(1:end).I in one go and then remove the those rows from the structure that I do not require.
For example
output(1).I has a length of 100X1
output(2).I has a length of 200X1
output(3).I has a length of 100X1
I want to remove output(2).I = [] and my final structure to only have output(1).I and output(3).I
Please advise.
  2 个评论
Rik
Rik 2018-3-26
Do you want to remove the structure element, or just empty out the field? The latter can be easily solved with a loop (and there may be several methods to do it faster), while the first is quite tricky (and will cause your elements to be renumbered).
Arif Ahmed
Arif Ahmed 2018-3-26
编辑：Arif Ahmed 2018-3-26
I want to remove the element. The indexing will be an issue and so I was thinking maybe there is an easy way to do it.

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采纳的回答

Jos (10584)
Jos (10584) 2018-3-27
L = arrayfun(@(k) numel(output(k).I), 1:numel(output))
output(L > 100) = [] ; % remove those elements of the structure array

更多回答（2 个）

Stephen23
Stephen23 2018-3-27
编辑：Stephen23 2018-3-27
Simpler:
len = arrayfun(@(s)numel(s.I),output);
output(len>100) = []
Or simplest:
len = cellfun('length',{output.I});
output(len>100) = []
Arif Ahmed
Arif Ahmed 2018-3-27
If I could I would accept all answers. Amazing guys! Thanks for the help.
Stephen Cobeldick, your code is really simple! Appreciate it.

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