You cannot subtract the image because the two images are of different dimensions. You can check this in your workspace. Consider, M is the length and N is the breadth of the original image. Then, the BW image would be " M x N " and the original (color image) would be " M x N x 3 " where the three represents the three color components (red, blue and green).
Off the top of my head, you could run a for loop as shown below.
new_image = zeros(size(original_image)); %initialize a new image where you would store your results
for kk = 1:3
for ii = 1:M
for jj = 1:N
if BW (ii, jj) ~= 0
new_img (ii, jj, kk) = original_image (ii,jj,kk);
end
end
end
end
new_image = uint8(new_image); %the new image would be in double.
imshow(new_image);
I would like to add that this might not be the most efficient way to do it.
Best of Luck!
