How can I remove the ranges from a specific column vector?

>> vec = [1;0;2;1;9;8;0;0;4;2;3;3;5;1;1;0;3;2;0;0;0;0;0;0];
>> tmp = reshape(vec,12,[])
tmp =
   1   5
   0   1
   2   1
   1   0
   9   3
   8   2
   0   0
   0   0
   4   0
   2   0
   3   0
   3   0
>> tmp(1:4,:) = []
tmp =
   9   3
   8   2
   0   0
   0   0
   4   0
   2   0
   3   0
   3   0
>> tmp(:)
ans =
   9
   8
   0
   0
   4
   2
   3
   3
   3
   2
   0
   0
   0
   0
   0
   0

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David Fletcher 2018-3-28

在 MATLAB Online 中打开

Neat. Easily beats my solution.

a=1:4
b=0:12:N;
c=a+repmat(b,4,1)';
del=reshape(c',1,numel(c))
k(del)=[]

Tuncay Eren 2018-3-29

Superb! Many thanks Stephan, David.

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Answer 2

David Fletcher 2018-3-28

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/391225-how-can-i-remove-the-ranges-from-a-specific-column-vector#answer_312422

在 MATLAB Online 中打开

del=[1:4 9:12 13:16]
k(del)=[]

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Tuncay Eren 2018-3-28

Thanks David.

İf k is a data vector as 1024x1, then how can we make it as a general formula to remove consecutive 4 bits and then keep 8 consecutive bits, then again remove 4 bits and keep 8 bits...

N=1024;

k=randi([0 1],N,1);

k_remove1=k(1:4);

k_remove2=k(13:16);

k_remove3=k(25:28);

.

Thanks

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