contains() does not recognize the second string as a valid

17 次查看(过去 30 天)
I am trying to use the "contains" function on elements of a cell and I am receiving an error:
>> temp = {'one', 'two', 'three'}
>> for i=1:length(temp)
>> contains(temp{1:i}, 't');
>> end
Error using contains
Unrecognized parameter name 't'. Parameter name must be 'IgnoreCase'.
Error in example (line 3)
contains(temp{1:i}, 't');

采纳的回答

MathWorks Support Team
The reason you are receiving this error is because temp{1:i} is outputting two strings.
>> temp{1:i}
ans =
'one'
ans =
'two'
Then, the "contains" function sees those two strings as the first two inputs to the function. It compares the string 'one' to the string 'two'. It then thinks the third input to the "contains" function is 't', but the third input can only be 'IgnoreCase', which is why you are receiving this error.
Change:
>> temp{1:i}
To:
>> temp{i}

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Dates and Time 的更多信息

产品


版本

R2017b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by